Which polynomial equation is a valid identity? A)
(6xy^2)^2 – (2xy)^2 = 4x^y^2(3x + 1)

B)
(6xy^2)^2 – (2xy)^2 = 4x^2y(3x + 1)(3y - 1)

C)
(6xy^2)^2 – (2xy)^2 = 4x^2y^2(3y + 1)(3y - 1)
D)
=
(6xy^2)^2 – (2xy)^2 = 12x^2y^2(3y + 1)(3y - 1)

Step-by-step explanation:

Answer is c

lmk if im wrong :)

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}