The initial temperature of a liquid is 50∘C. After which changes in temperature will the liquid be the same as the initial temperature?

45.2

Step-by-step explanation:

Explanation:

The idea here is that you need to use the mass of water, the heat added to the sample, and the specific heat of water to find the resulting change in temperature.

The equation that establishes a relationship between heat absorbed and change in temperature looks like this

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed

m

- the mass of the sample

c

- the specific heat of water, equal to

4.18

J

g

∘

C

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values and solve for

Δ

T

- do not forget to convert the added heat from kilojoules to Joules

q

=

m

⋅

c

⋅

Δ

T

⇒

Δ

T

=

q

m

⋅

c

Δ

T

=

1.0

⋅

10

3

J

50.0

g

⋅

4.18

J

g

∘

C

=

4.785

∘

C

So, if the temperature of the water changed by

4.785

∘

C

, and its final temperature is now

50.0

∘

C

, it follows that its initial temperature was

Δ

T

=

T

f

−

T

i

⇒

T

i

=

T

f

−

Δ

T

T

i

=

50.0

∘

C

−

4.785

∘

C

=

45.2

∘

C

i belive those are the ones that are under 90 degreese.

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).