The sum of a two-digit number and the number obtained by reversing the digits is 66. If the digits of the number differ by 2, find the numbers which satisfy this condition.

4 and 2

Step-by-step explanation:

a + b = 6

a - b = 2

Sum these equations, we get 2a = 8, then a = 4

Substitute to one of these equations, we get 4 - b = 2, so b = 2

Prove: The sum of 24 and 42 is 66, and 4 and 2 differ by 2 are both correct!

idk

step-by-step explanation:

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.