Which function has zeros of -8, 1, and 3? O A. y= (x - 3)(x + 8)(x - 1)
OB. y=(x + 1)(x-8)(x + 3)
O C. y= x(x + 8)(x - 3)
OD. y = x(x + 3)(x-8)

the answer should be A

Step-by-step explanation:

Hope this helps!

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

step-by-step explanation:

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