Solve the system of equations by using substitution. \mathrm{y}=2\mathrm{x}+3\newline \mathrm{y}=\mathrm{x}+2y=2x+3 y=x+2 \left(\mathrm{x},\mathrm{y}\right) =(x, y)=

Step-by-step explanation:

It looks like your equations are

y = 2x + 3

y = x + 2

Using substitution, since the expressions, 2x+3 and x+2 are both equal to y, then they must be equal to each other.

2x+3 = x+2

Subtract x from both sides (this removes the x from the right side of the equation and we'll only have x on the left side)

x+3 = 2

Then subtract 3 from both sides if the equation.

x = -1

Almost finished! You still have to find y. You can use either of the original equations to find y. Use x = -1 in one of the equations. Let's use y = 2x + 3

y = 2x + 3

y = 2*(-1) + 3

y = -2 + 3

y = 1

So you found x=-1 and y=1. These are the answers because this pair makes both of the original equations true. We can write them in an ordered pair, like this:

(-1, 1)

Inside the parenthesis, the first number is the x and the second number is the y

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.