A standard fair die is rolled one time. What is the probability that it lands on a number greater than 3 or on an even number?

The die is assumed to have six sides labeled  

1

,

2

,

3

,

4

,

5

,

6

The numbers greater than 5 are  

6

.

The numbers less than 3 are  

2

,

1

.

So the numbers greater than 5 OR less than 3 are the union of the two sets or 6, and 2,1. The probability of rolling one of these numbers is  

3

6

=

1

2

or  

50%  

.

Step-by-step explanation:

Sorry its sloppy

if you was gonna solve for a, a is a   < -12

yes

step-by-step explanation: