Find an algebraic solution that shows three consecutive integers, with the second and third adding up to -17

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

for future students the answer is b

hope i

-lavira: )

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)