Challenge An airplane is preparing to land at an airport. It is 36,000 feet above the ground and is descending at the rate of 3,200 feet per minute. At the same airport, another airplane is taking off and will ascend at the rate of 2,800 feet per minute. When will the two airplanes be at the same altitude and what will that altitude be? Use pencil and paper. Use two other methods to solve the problem. Explain which methods are easier to use and which are more difficult to use for the situation They will be at the same altitude in _ minutes, when their altitude will be _ feet.

6 seconds., 16800 feet

Step-by-step explanation:

The first plane is going y = -3200x + 36000

The second plane is going y = 2800x

Substitute the second equation for y into the first one:

2800x = -3200x + 36000

6000x = 36000 (Add 3200x to both sides)

x = 6 (Divide each side by 6000)

That means they will be the same altitude at 6 minutes.

To find how high, put your answer into one of the equations.

y = 2800 (6)

y = 16,800 feet

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.