A line passes through the points (-4,1) and (-3,3). This line can be modeled by the equation y = mx + b. Complete the table to determine the values of m and b.

m = 2, b = 9

Step-by-step explanation:

Find m (the slope) by subtracting y1 - y2 (1 - 3 = -2) and x1 - x2 (-4 - -3 = -1). Put the y answer on top of the x answer and simplify. -2/-1 = 2 because the negatives cancel each other out.

Find b by substituting one of the coordinates into the problem.

y = mx + b

1 = 2(-4) + b

1 = -8 + b

9 = b

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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