A train has eleven train cars. At least eleven passengers are in every train car. No three neighboring train cars have more than fifty passengers all together. What is the
maximum possible number of passengers on the train?

the answer is 0052

0 0 5 2

5 0 2 6 3 5

− 0

2 6

− 0

2 6 3

− 2 5 0

1 3 5

− 1 0 0

3 5

m∠abd = m∠dbc

step-by-step explanation:

given : ab bisects ∠dbc

as we know that bisection means ab divides   ∠dbc   in two equal angles named as   ∠dba and   ∠abc

so, m∠abd = m∠dbc  

because ab bisects ∠dbc.

hence , the first statement m∠abd = m∠dbc is true.

14 x 10 5

step-by-step explanation:

10 5 = 100,000

14x10,000 = 140,000