Which is the graph of f(x) = 2(3)*?

First option (top left)

Step-by-step explanation:

Since the coefficient of this equation, , is 2, when x is 0, then y must be 2. The graph must have a y-intercept of 2. You can find this by plugging this in.

I cannot see the fourth graph, but the second graph does not have a y-intercept of 2, therefore it can immedeately be ruled out.

Then we plug in the coordinates they give.

It just so happens that the first one, is indeed equal to 6.

We can check that this is right by disproving the third one (top right).

, not 8, therefore our third answer choice is false.

The fourth one is definetly wrong because the y-value at x=2 (as we have already calculated) is 18, not 12.

Therefore, our first answer, the one on the top left, is correct.

note: for this problem you did not even need to find the y-intercepts. Plugging in the coordinates would be fine by its own (the second answer choice is already wrong just because of the coordinates since 9≠6(found in answer choice 1)). However, having the y-intercept handy will be very helpful if there is more than one answer choice with correct coordinates.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the answer to this is a. a^2 + b^2 = c^2