Suppose that the 24X is scheduled to arrive at the North Hall Busloop on the hour and on every half-hour (e. g. 9, 9:30, 10, 10:30, etc.). In actuality, however, the arrival time is uniformly distributed over an interval containing 20 extra minutes on either side of the scheduled arrival time; for example, if the scheduled arrival time is 11:00am then the true arrival time is uniformly distributed on [10:40 am, 11:20 am]. Let X denote the number of busses arriving between 11:10am and 11:20am. Additionally, assume that busses arrive independently of one another. Required:
What is the support of X?

step-by-step explanation:

idk

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!