Solve the following equation

Hi,

x² + 8x + 12 = 0

a= 1 ; b= 8 c= 12

∆ = b² - 4ac

∆ = 8² - 4*1*12

∆ = 64 - 4*12

∆ = 64 - 48

∆ = 16

∆>0 :

x1 = (-b-√∆)/2a = (-8-4)/2 = -12/2 = -6

x2 = (-b+√∆)/2a = (-8+4)/2 = -4/2 = -2

S= { -6 ; -2 }

x = -6

or x = -2

✅(•‿•)

if you was gonna solve for a, a is a   < -12