The 11th term of the AP -3, -1/2, 2 . is

Given AP is -3 ,-1/2,2,..

First term = -3

Common difference = (-1/2)-(-3)

⇛d = (-1/2)+3

⇛d = (-1+6)/2

⇛ d = 5/2

We know that nth term = an = a+(n-1)d

11th term = (-3)+(11-1)(5/2)

⇛a 11 = -3+(10)(5/2)

⇛a 11 = -3+(5×5)

⇛a 11 = -3+25

⇛ a 11 = 22

11th term of the AP = 22.

also read similar questions: The 3 rd term of an AP is 3 and 11th term is -21, find its first term and common difference

The 4th term of ap is 10 and the 11th term of it exceeds 4th term by 1 find the sum of 20 terms

2

Step-by-step explanation:

initial term = -3

common difference = .5

-3 + .5 for 11 times from 3 = positive 2

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3