1. Divide: (x^2-10x+30) + (x-5) o x-10-6
o x-5- 5/x-5
o x-10- 30/x-5
o x-5+ 5/x-5

2. Divide: (x^3 -20x+16) + (x-4)
o -x^2+4x+4
o x^2+4x-4
o -x^2-4x+4
o x^2-4x+4

(didnt want to type 3 and 4 so theyre in the picture pls help)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

huh? im pretty sure it is in 199

step-by-step explanation:

by definition, an arc subtended by a central angle of some given measure has the same measure. so .