We will say that a positive integer is cube-free if there is no integer such that . Let be the set of all cube-free integers. We will say that a positive integer is modest if every prime factor of is less than 10 (i. e., 2, 3, 5 or 7). Let be the set of all modest integers. What is (i. e., how many cube-free modest integers are there)

2

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

answer: i don't understand it

step-by-step explanation: sorry

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560