5x+3y=2y−3 Step 2 of 2 : Find the equation of the line which passes through the point (6,−10) and is perpendicular to the given line. Express your answer in slope-intercept form. Simplify your answer.

Idon't see any graph, however the graph of the function : f(x) = x²-2x+3 is a parabola: 1) open upward (since a> 0)2) it intersects y-axis in 3 (y=3)3) its axis of symmetry is x = +1 ( -b/2a)4) it's minimum is y = -2, so its vertex is (1,-2)5) it doesn't intersect the x-axis since discriminant < 0