Need help again... :>

(using this as an excuse to give out brainliest :P)

The equation of a line in slope-intercept form is y=mx+b. “m” is the slope and “b” is the y-intercept. To find the slope, take two points and plug them into the slope formula. The slope formula is Y2-Y1/X2-X1.

You can use any two points on the graph but I will use (3,-2) and (6,-3).

-3-(-2)/6-3

-3+2/3

-1/3

The slope is -1/3. To find the y-intercept, look the y-value where the line touches the y-axis. In this graph, the line touches the y-axis at (0,-1).

So, the equation of the line in slope-intercept form is y=-1/3-1.

Hope this helps! :)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

answer: i think it is (1,-2)