In a group of 50 students 38 play chess and 24 play scrabble. How many plays both chess and scrabble.

12

Solve:

to solve, first add both partial numbers together

38 + 24 = 62

then subtract the whole number

62 - 50 = 12

Step-by-step explanation:

the way this works is the overflow when adding the two numbers, is the amount of students that do both, they count in both groups meaning their counted twice, this means that if each student dropped a coin for what they played (1 for chess and/or 1 for scrabble) the 12 students who played both would drop two coins

not a professional explanation but i hope it makes sense ^^

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540