Find the general solution of the given differential equation. y'''-10y''+25y'=0 y(0)=3 y'(0)=4 y''(0)=5

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

What is the length of the segment joining the points at (4,5) and (6,-2) round to the nearest tenth if necessary

Ateacher noticed 5/8 of the students were wearing either blue shorts or white shorts. write two different ways this could be done.