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Mathematics, 02.12.2021 18:00, shaylawaldo11
Limx→∞[8exx+1(x−1)!−−−−−−−−−−√x−8x2 −4xlnx−ln2x−(4x+2lnx)ln2π]
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Answers: 1
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Limx→∞[8exx+1(x−1)!−−−−−−−−−−√x−8x2 −4xlnx−ln2x−(4x+2lnx)ln2π]...
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