Can someone get this? Ive been trying and cant get it

Given :-

To Find :-

Answer :-

The roots of the function are 5 and -3 . In general we can write the Quadratic function with roots π and ∆ as ,

f(x) = ( x - π )(x-∆)

So on using this we have ,

f(x) = ( x -5)( x -(-3))

f(x) = (x-5)(x+3)

f(x) = x(x-5)+3(x-5)

f(x) = x² -5x +3x -15

f(x) = x² -2x -15

Hence the required answer is x² -2x -15.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

no solution

step-by-step explanation:

there is not enough information in the problem to solve.