Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of - 39.76°C and a boiling point of 388. 23°C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C F - 32)
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Express the range as an inequality and in interval notation
Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid state?
(Type an inequality or a compound inequality. Simplify your answer. Use integers or decimals for any numbers in the expression. Round to three decimal places as
needed.)

c

step-by-step explanation:

i think because what else can be a sample of every member

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

step-by-step explanation:

total income = price of one ticket   *   number of tickets sold

  y                 =     4                                   x

so the equation is y=4x     with x≥0   because number of tickets sold can not be negative

thus the equation is a semi -line with an end point at

(0,0)

passing through :

x=1     y=4(1) = 4   so through (1,4)

im not preaty sure about that

step-by-step explanation: ax^2+bx+c=0= these nuts