Can you help me! Determine the solution to the following one-variable linear equation:

a. 4a - 11 = 2a + 3
b. 3z + 12 = 15
c. 2 - 6b = 20
d. 3y - 5 = 27 - y

Hi,

4a - 11 = 2a + 3

4a - 11 + 11 = 2a + 3 + 11

4a = 2a +14

4a - 2a = 2a - 2a + 14

2a = 14

2a / 2 = 14 / 2

a = 7

3z + 12 = 15

3z + 12 - 12 = 15 - 12

3z = 3

3z / 3 = 3 / 3

z= 1

2 - 6b = 20

2 - 2 - 6b = 20 - 2

- 6b = 18

6b = - 18

6b / 6 = -18 / 6

b= -3

3y - 5 = 27 - y

3y - 5 + 5 = 27 - y + 5

3y = - y +32

3y + y = - y + y +32

4y = 32

4y / 4 = 32 / 4

y= 8

✅(◠‿◕)

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

the answer is a.

step-by-step explanation:

in three games of golf, alex shot two under par four times.