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Mathematics, 01.12.2021 02:40, danaya111
A curve has vector equation ������(������)=⟨ln(sin������),ln(co s������),2‾√������⟩, where 0<������<������/2. Find an equation of the osculating plane to the curve at the point (−ln22,−ln22,������22‾√).
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A curve has vector equation ������(������)=⟨ln(sin������),ln(co s������),2‾√������⟩, where 0<����...
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