Mathematics, 30.11.2021 22:00, tayler1911
An object is launched straight up into the air at an initial velocity of 64 feet per second. It is launched from a height of 6 feet off the ground. Its height H in feet, at t seconds is given by the equation H=-16t^2*64t+6. Find all times t that the object is at a height of 54 feet off the ground.
Answers: 3
Mathematics, 22.06.2019 02:30, samueldfhung
Solve the system of equations. x=-2y+1 and x+2y=9. show work
Answers: 1
Mathematics, 22.06.2019 04:00, cardsqueen
Julia spends $5.25 on gas for her lawn mower. she earns $13.00 mowing her neighbor's yard. what is julia's profit?
Answers: 1
Mathematics, 22.06.2019 05:50, xuzixin2004
What is the solution for the system of equations below? y=3/4x-12 and y=-4x-31. a: (-4,-15). b: (-4,-12). c: (4,-9). d: (4,-47)
Answers: 2
An object is launched straight up into the air at an initial velocity of 64 feet per second. It is l...
History, 22.03.2021 18:40
English, 22.03.2021 18:40
Health, 22.03.2021 18:40