Which is a possible set or rigid motions make the statement true? A. f(x, y) = (x + 4, y - 6)

B. f(x, y) = (2x, 2y)

C. f(x, y) = (2x + 4, 2y)

D. f(x, y) = (x/2, y/2)

I need an answer ASAP

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

what is the original number? you forgot to add it.