Two bowlers bowl the following number of strikes in 9 games

what is the mean and the mean absolute deviation of the number of strikes of each bowler

1st bowler 8,5,5,6,8,7,4,7,6
2nd bowler 10,6,8,8,5,5,6,8,9

what does the mean absolute deviation suggest about each bowler's consistency?

First, let's calculate the mean and the mean absolute deviation of the first bowler.

FIRST BOWLER: 8,5,5,6,8,7,4,7,6
Mean = (Sum of all data)/(Number of data points) = (8+5+5+6+8+7+4+7+6)/9
Mean = 6.222
Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points
MAD = [|8 - 6.222| + |5 - 6.222| + |5 - 6.222| + |6 - 6.222| + |8 - 6.222| + |7 - 6.222| + |4 - 6.222| + |7 - 6.222| + |6 - 6.222|]/9
MAD = 1.136

SECOND BOWLER: 10,6,8,8,5,5,6,8,9
Mean = (Sum of all data)/(Number of data points) = (10+6+8+8+5+5+6+8+9)/9
Mean = 7.222
Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points
MAD = [|10 - 7.222| + |6 - 7.222| + |8 - 7.222| + |8 - 7.222| + |5 - 7.222| + |5 - 7.222| + |6 - 7.222| + |8 - 7.222| + |9 - 7.222|]/9
MAD = 1.531

The mean absolute deviation represents the average distance of each data to the mean. Thus, the lesser the value of the MAD is, the more consistent is the data to the mean. Between the two, the first bowler is more consistent.

Ithink the answer is d. not sure but don’t answer it.