On a coordinate plane, a curved line with a minimum value of (0, 1) and a maximum value of (negative 1. 3, 2. 2), crosses the x-axis at (negative 2. 2, 0) and crosses the y-axis at (0, 1). Which statement correctly identifies a local minimum of the graphed function? Over the interval [â€"3, â€"2], the local minimum is 0. Over the interval [â€"2, â€"1], the local minimum is 2. 2. Over the interval [â€"1, 0. 5], the local minimum is 1. Over the interval [0. 5, 2], the local minimum is 4.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

answer: 800

step-by-step explanation:

15: 24

62.5%

step-by-step explanation: