Solve 2 cot x = csc^2 x symbolically on the interval (0,2pi).

x=pi/4, 5pi/4

Step-by-step explanation:

cot x = cos x / sin x, csc x = 1/sin x, so we have 2 cos x / sin x = 1/ sin^2 x. multiply both sides by sin^2 x to get 2 cos x * sin x = 1, divide both sides by 2 to get cos x sin x = 1/2, this would work for angles pi/4 and 5pi/4 (3pi/4 and 7pi/4 would make cos x sin x = -1/2) since cos x = sin x = sqrt(2)/2

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.