Mathematics, 27.11.2021 08:40, gadgetady5699

Given that rectangle ABCD has coordinates A(0,0), B(12,0), C(12,6), and D(0,6), F is the midpoint of AB¯¯¯¯¯, and G is the midpoint of CD¯¯¯¯¯, which of the following proves that FB=GC? 1. By the Distance Formula, the coordinates of F are (6, 0) and the coordinates of G are (6, 6).
Then FB = 12, and GC = 12.
Thus FB = GC.

2. By the Distance Formula, the coordinates of F are (6, 12) and the coordinates of G are (6, 0).
Then FG = 6, and GC = 6.
Thus FG = GC.

3. By the Midpoint Formula, the coordinates of F are (6, 0) and the coordinates of G are (6, 6).
Then FB = 6, and GC = 6.
Thus FB = GC.

4. By the Midpoint Formula, the coordinates of F are (6, 6) and the coordinates of G are (6, 0).
Then FB = 6, and GC = 6.
Thus FB = GC.

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Given that rectangle ABCD has coordinates A(0,0), B(12,0), C(12,6), and D(0,6), F is the midpoint of...