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If a = 8 and b = 36 calculate the value of a^(1/3) b^(-3/2)
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How do you create a data set with 8 points in it that has a mean of approximately 10 and a standard deviation of approximately 1?
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If a = 8 and b = 36 calculate the value of a^(1/3) b^(-3/2)...
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