Mathematics
Mathematics, 26.11.2021 03:10, kalo1023

The position vector of a particle of mass 0.05 kg is r (t) = 3 cos (4. t)i + 3 sin (4.t)j +10 t k What is the vector expression for the velocity of the particle at time t in m/s?
v (t) = ?

What is the vector expression for the acceleration of the particle at time t in m/s^2?
a(t) = ?

Deduce the magnitude of the force acting on the particle
|F| =

What is the direction of the acceleration compared with the velocity of the particle?

answer
Answers: 2

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The position vector of a particle of mass 0.05 kg is r (t) = 3 cos (4. t)i + 3 sin (4.t)j +10 t k...

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