A couple stayed for 3 years before having their first child. then 2 years before the second. 2 years again before the third, and so on until the sixth child. If the husband was 28 years and the wife was 25 years when they had their first child, what is the sum of the ages of the couple a year before the last born?

no

explanation:

you can be freinds, and people but not follow people.

a long term investor

step-by-step explanation:

because he is a long term investor

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.