(I’m having trouble with this question, it would be greatly appreciated if I could have some help, thank you) What is the equation of a line that is parallel to – 2x + 3y = -6 and passes through the point (-2, 0)?

y = 2/3x + 4/3

Step-by-step explanation:

you need to know the slope of the line -2x + 3y = -6 because parallel lines have the same slopes

let's put the equation in y=mx+b format (slope-intercept format)

-2x + 3y = -6

add 2x to each side to get:

3y = 2x - 6

divide each side by 3 to get:

y = 2/3x - 2

the equation now shows us the slope is 2/3 and the y-intercept is (0,-2)

now we use y=mx+b again and use the point (-2,0) and the m=2/3 to get the y-intercept ('b' value) of the equation that is parallel:

0 = 2/3(-2) + b

0 = -4/3 + b

b = 4/3

equation would be:

y = 2/3x + 4/3

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363