A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadratic function p (t) = 1/2gt + vot + po, where t > 0, g is -32 ft/sec/sec, vo is initial velocity, and po is its initial position above the ground. If the ball was thrown straight up at 16 ft/sec when it was 5 ft above the ground, how high did it go?