What is the solution to the trigonometric inequality 2sin(x) + 3 > sin^2(x) over the interval 0≤ x ≤ 2pi radians?

$32,660

step-by-step explanation:

quit

step-by-step explanation:

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

it's a proportional graph.

step-by-step explanation:

8 x 5 = 40         (and you have -8x and -5y)

x= absiss

y= orderly

so you have a proportional graph.