Three integers sum to 57. The second integer is twice the first integer. The third integer is seven less than five times the first integer. What are the three integers?

a=8

b=16

c=33

Step-by-step explanation:

Let's call the integers a, b, and c. (a is the first, b is the second, and c is the third.)

a+b+c=57

Write the second two sentences as equations.

b=2a

c=5a-7

Plug in these values of b and c to the original equation.

a+(2a)+(5a-7)=57

Solve for a:

a+2a+5a-7=57

8a-7=57

8a=64

a=8

Now, plug in your solution for a into the equations for b and c to solve for them.

b=2a=2(8)=16

c=5a-7=5(8)-7=40-7=33

You can add up your answers for a, b, and c to make sure you're correct.

a+b+c=8+16+33=57

I hope this helped!

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: 88

step-by-step explanation: