What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)? y = – Five-halves x – 1
y = – Five-halvesx + 5
y = Two-fifthsx – 1
y = Two-fifthsx + 5

First, let’s rearrange the equation in terms of y:

y = -2.5x + 6

We can input the coefficient of x (the gradient of the line) above into this equation:

y - y1 = m (x - x1)

Where y1, is the y value of an arbitrary point in the line, m is the gradient of the line, and x1 is the corresponding x value of the same arbitrary point in the line for y1.

So, putting it in we get:

y - 4 = -2.5(x +2)

y -4 = -2.5x - 5

y = -2.5x -1

Step-by-step explanation:

30005

yes ok