Brooklake town had only 50 social housing units when the new social programme started. Since then it has been adding new social housing units at a steady rate. Now17 years later, the town has a total of 322 sacial housing units.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

150.6

all i did was i multiplied 5.02 by 30