If Y has exactly 2 positive integer factors then Y is a prime number. if so how?

Step-by-step explanation:

yes, if your teacher meant to include the default factors of every positive integer number : 1 and the number itself.

these are the 2 positive integer factors.

if a positive number can only be divided without remainder by 1 or by itself (with result 1), then it is per definition a prime number.

if the number can be divided without remainder by another number, then we are not dealing with a prime number.

but if your teacher did not have these default factors in mind, then no :

example : 15

15 has only 2 factors : 3 and 5.

both are positive integer numbers.

and yet 15 is not a prime number.

but back to my first point, 15 also has formally the factors 1 and 15. so, if we count them too, then we have suddenly 4 factors. and the original statement fits again.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

true

step-by-step explanation: