Assume that adults have iq scores that are normally distributed with a mean of u = 105 and a standard deviation =20 find the probability that a randomly selected adult has an iq less than 129

P(X<129) ≈ 0.8849

Step-by-step explanation:

I've attached a graph of the normal distribution to help you visualize the problem. To calculate this on a TI-84, we can use the normalcdf function to find the area between the end of the left-tail of the normal distribution to x=129, hence, we are finding P(X<129). We can write this as normalcdf(-1e99,129,105,20) ≈ 0.8849, therefore, the probability that a randomly selected adult has an IQ less than 129 is about 0.8849 or about 88.49% likely to occur.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

step-by-step explanation: