Solve the pair of equation
2x – y=9
4x^2 + 3y^2– 2x + y = 16

Step-by-step explanation:

1) Solve for 2x - y = 9

A. Solve for y.

2x - y = 9

B. Subtract 2x from both sides.

-y = 9 - 2x

C. Multiply both sides by -1.

y = -9 + 2x

D. Regroup terms.

y = 2x - 9

2) Substitute y = 2x- 9 into 4x² + 3y² - 2x + y = 16

A. Start with the original equation.

4x² + 3y² - 2x + y = 16

B. Let y = 2x - 9.

4x² + 3(2x - 9)² - 2x + 2x - 9 = 16

C. Simplify.

16x² - 108x + 234 = 16

3) Solve for x in 16x² - 108x + 234 = 16

A. Solve for x.

16x² - 108x + 234 -= 16

B. Move all terms to one side.

16x² - 108x + 234 - 16 = 0

C. Simplify 16x² - 108x + 234 - 16 to 16 x² - 108x + 218

16 x² - 108x + 218 = 0

D. Use the Quadratic Formula.

,

E. Simplify solutions.

4) Substitute into y = 2x - 9.

1) Start with the original equation.

y = 2x - 9

2) Let x =

3) Simplify

were is the equation

none cuz there are no "following statements" regarding the question

step-by-step explanation: