Solve 9x + 3y = 15 for y. A. y=-3x + 15
B. y = 9x + 15
C. y = -9x + 5
D. y=-3x + 5

D) y = -3x + 5

Step-by-step explanation:

Move x.

3y = -9x + 15

Divide by 3.

y = -3x + 5

Hope it helps :) and let me know if you want me to elaborate.

D. y = -3x + 5

Step-by-step explanation:

Subtract 9x from both sides

3y = 15 - 9x

y = 15/3 - 9x/3

y = 5 - 3x

y = -3x + 5

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)