You are given to odds against tossing three with three coins, meaning you win $4 if you succeed and you lose $ 1 if you fail. Find the expected value (to you) of the game. Would you expect to win or lose money in 1 game? In 100 games? Explain.

To find the E(X) expected value, you come up with the different probabilities for each outcome

your set of outcomes after 3 tosses would be = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} where H is heads and T is tails

Each element has a probability of 1/8 so let x represent number of tails

Probability (x) = P (x)

P (0) = 1/8

P (1) = 3/8

P (2) = 3/8

P (3) = 1/8

The E(x)=Summation (x times P(x))

E ( X ) = (0) (0.125) + (1) (0.375) + (2) (0.375) + 3 (0.125) = 1.5

Now which probability is 1.5 tails? None, so it is either 2 tails or 1 tails

So you can expect to lose money in 1 game

But as you play more games the probability of getting 3 tails becomes more and more likely, so you can expect to win in a 100 games

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step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet