The cost of admission to a festival was $112 for 9 children and 3 adults. The admission was $108 for 8 children and 3 adults in another festival. How much was the admission for each child and adult?

cost of admission for each child was $4.00, and each adult was $25.33

Step-by-step explanation:

When solving questions like these , I like to break down the problem so I understand it better.

Let x ---> cost of the admission for each child

Y > cost of the admission for each adult

9x+3y = 112 ---> equation A

8x + 3y = 108 ---> equation B

Subtract B from A

9x+3y=112

-8x+3y = 108

x = 112-108

x = 4

Find value of y by substituting value of x into equation

9(4)+3y=112

Solve for y

36+3y = 112

3y = 112=36

3y = 76

y = 25.33

step-by-step explanation:

if x = 2 you have to find x to finish the problem

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950