Please help algebra. quadratic formulas
Please specify question number in your answer.

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Step-by-step explanation:

Area of a trapezoid =

height * ( sum of base lengths) / 2

So...let the height = h

One base = h + 3

And the other is h + 5

So...we have this

375 = h [ (h + 3 + h + 5 ] / 2 multiply both sides by 2

750 = h [ 2h + 8 ]

750 = 2h^2 + 8h rearrange as

2h^2 + 8h - 750 = 0

Using the quadratic formula....we get the answer ≈ 17.468 = 17.5 yards (rounded)

"b" is correct

For the quadratic equation

ax2+bx+c=0

the formula for the roots is

x=−b±√b2−4

ac2a(1)

Identify the values for

a,b,&cx2+4x+3=0

cmp

ax2+bx+c=0a=1b=4c=3(2)

Substitute these numbers into eh formula

x=−4±√42−(4×1×3)2×1(3)

Carefully proceed and do the calculations

x=−4±√16−122x=−4±√42x=−4±22

now calculate the two separate solutions

x1=−4+22=−22=−1x2=−4−22=−62=−3

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.

you first to choose the points and then move from then as the slope you have