Calculate the mean and median of each data set, and determine what type of distribution it has. Data Set 1 5 8 9 6 3 2 10 8 5 4 3 Data Set 2 8 7 3 2 4 6 2 7 4 9 6
5 5.27 6 5.73 5.55 skewed right skewed left symmetric

Data Set 1:

Mean = 5.73

Median = 5

Data Set 2:

Mean = 5.34

Median = 5.64

Step-by-step explanation:

To find the mean, you need to add up all the data, and then divide this total by the number of values in the data.

Data Set 1:

5 + 8 + 9 + 6 + 3 + 2 + 10 + 8 + 5 + 4 + 3 = 63

There are 11 values, so you divide the total by 11:

63 ÷ 11 = 5.7272.. ≈ 5.73

Data Set 2:

8 + 7 + 3 + 2 + 4 + 6 + 2 + 7 + 4 + 9 + 6 + 5 + 5.27 + 6 + 5.73 + 5.55 = 85.55

There are 16 values, so you divide the total by 16:

85.55 ÷ 16 = 5.34

To find the median, you need to put the values in order, then find the middle value. If there are two values in the middle then you find the mean of these two values.

Data Set 1:

The numbers in order:

2, 3, 3, 4, 5, (5), 6, 8, 8, 9, 10

The middle value is marked in brackets, and it is 5.

So the median is 5

Data Set 2:

2, 2, 3, 4, 4, 5, 5.27, (5.55, 5.73), 6, 6, 6, 7, 7, 8, 9

This time there are two values in the middle. They have been in brackets The median is found by calculating the mean of these two values:

(5.55 + 5.73) ÷ 2 = 5.64

So, the median is 5.64

-TheUnknownScientist 72

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times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct