Line perpendicular to P(t)=3t+4 and passing through the point (3,1)

P(t) = -1/3 + 1

Step-by-step explanation:

to find this out, we must use the slope perpendicular to 3

perpendicular slopes are the slope's reciprocal's negative, which in this case it is -1/3

to find the line with the points (3,1), we simply use the equation y = -1/3x + b and then plug them in

1 = -1/3(3) + b

1 = -1 + b

b = 2

the y intercept is 2 and so we can write the equation like this:

P(t) = -1/3t + 2

answer: the common difference is -0.10

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