What is the sum of fist one hundred positive multiples of 3? I’ll mark you brainliest and give 100 points!

The solution to the given problem can be obtained by sum formula of arithmetic progression.

In arithmetic progression difference of two consecutive terms is constant. The multiples of any whole number(in sequence) form an arithmetic progression.

The first multiple of 3 is 3 and the 100th multiple is 300.

3, 6, 9, 12,... 300. There are 100 terms.

The sum 3 + 6 + 9 + 12 + ... + 300 can be obtained by applying by sum formula for arithmetic progression.

Sum = (N/2)(First term + Last term)

where N is number of terms which in this case is 100.

First term = 3; Last term = 300.

Sum = (100/2)(3 + 300) = 50 x 303 = 15150.

Step-by-step explanation:

Brainliest please tysm

answer: there are x+184 pages in olivia's book.

step-by-step explanation:

let the total number of pages in the book which olive has already read be x.

then if olive has 184 pages left to read, then the total number of pages are in olive's book= pages she has read+pages she has left to read

therefore, the total number of pages in olivia's book=

hence, there are x+184 pages in olivia's book.